Тема: Use Gauss-Jordan elimination to find solutions.?

Early life and education Karl Friedrich Gauss was born in Brunswick, Germany, on April 30, 1777. He was the son of Gebhard Dietrich Gauss, a.

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Welcome to MathPortal. This web site owner is mathematician Miloš Petrović. I designed this web site and wrote all the lessons, formulas and calculators.

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Systems of equations with elimination: x+2y=6 & 4x-2y=14 Systems of equations with elimination: -3y+4x=11 & y+2x=13 Systems of equations with elimination.

Click here gauss elimination method solved problems

Early life and education Karl Friedrich Gauss was born in Brunswick, Germany, on April 30, 1777. He was the son of Gebhard Dietrich Gauss, a.

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Welcome to MathPortal. This web site owner is mathematician Miloš Petrović. I designed this web site and wrote all the lessons, formulas and calculators.

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here s the tutorial on it http://www.assignmentexpert.com/blog/gaussian-elimination-method-for-solving-systems-of-linear-algebraic-equations/

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You have three equations and three unknowns. Use the first equation to solve for x. Place this value of x into the second and third equations: 2(1-y) = z 2z = -2-y The second equation is a solution for z. Use this in the third equation, 2(2(1-y)) = -2-y 4-4y = -2-y 6=3y y=2 Now work your way backwards and solve for z, then x. 2(1-y) = z 2(1-2) = -2 = z Finally, x=1-y = 1-2 = -1 There is an easier way to do this using matrices. Notice that the three linear equations above look like this: 1x + 1y + 0z = 1 2x + 0y -1z = 0 0x + y + 2z = -2 In matrix form this is A w = b 1 1 0 |x| 1 2 0 -1 |y| = 0 0 1 2 |z| -2 The solution w is A^(-1)b. On your calculator you can take this matrix to the negative 1 power, multiply it by b and all three of your answers x, y, and z will come out at once. Such is the power of linear algebra.