Тема: Homework Questions? Ask a Teacher or Tutor Online

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A. Erosion.

Well let me do my homework and study for my test tomorrow

Pose to b doing homework and studying

Juan is the poster child for Fake News.He makes up lies instead of doing his homework.It happens every night. I switch channels when he"s on

First, if you cannot visualize the situation, DRAW A PICTURE! M is the midpoint of AC, so AM = MC = (1/2) AC P is the midpoint of MC, so MP = PC = (1//2) MC = (1/4) AC Similarly, since N is the midpoint of BC and Q is the midpoint of NC, you can show that QC = (1/4) BC Both triangle ABC and triangle PQC have the same angle at C, and side PC is 1/4 the length of side AC and side QC is 1/4 the length of side BC. Therefore, the two triangles are similar, by side-angle-side similarity.

I"m ready for Cali and NC, can time go faster? Just want the homework to stop

Guess I"ll do my homework and get some sleep

Sitting at work doing homework.

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And if they do a little homework, they will find that a lot of people on socialized medicine come to the US for surgeries.

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Guys today may be the best day of the year so far. I woke up. Watched the Office. Got a 100% on my homework. Worked at 315. Princess parking

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Unheeee my homework, cry baby!

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Like I said do more homework. Frank played with grown men. And the league would smack NC State. Your boi couldn"t even make them.500

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India is loosing ground. Time for all opposition to do good homework. We want progress and not regress

I think you can probably assume that the skier isn t doing any pushing but is just letting gravity do the work without the non-conservative forces like friction to waste energy the ME(total) = KE + GPE is conserved so without any NC forces the skiers KE at the lower level = (1/2)mv(i)² + mg[h(i) - h(f)] = (1/2) * 65.7 * 15.5² + 65.7 * 9.8 * (1222 - 959) BUT the actual KE at the lower level = (1/2) * 65.7 * 25.8² so ΔKE at lower level = (1/2) * 65.7 * 25.8² - [(1/2) * 65.7 * 15.5² + 65.7 * 9.8 * (1222 - 959)] ΔKE at lower level = -155361 J [negative b/c energy is lost to the NC forces] The work done against the skier s motion = the change in the KE due to the NC forces so F(average) * s = ΔKE at lower level F(average) * 380.0 = -155361 F(average) = -409 N (to 3 sig figs). [negative b/c it opposes the skier s motion] so the magnitude of the average combined non-conservative force acting against the skier during the given interval is 409 N Another way to do it (with just one calculation) is to use the energy formula like this: KE(i) + GPE(i) + W(non-con) = KE(f) + GPE(f) W(non-con) = (1/2)mv(f)² + mgh(f) - (1/2)mv(i)² - mgh(i) F(average) * s = (1/2)mv(f)² + mgh(f) - (1/2)mv(i)² - mgh(i) F(average) = [(1/2)mv(f)² + mgh(f) - (1/2)mv(i)² - mgh(i)] / s F(average) = {(1/2)m[v(f)² - v(i)² + 2gh(f) - 2gh(i)]} / s = {(1/2) * 65.7 [25.8² - 15.5² + 2 * 9.8 * 959 - 2 * 9.8 * 1222]} / 380.0 = -409 N (to 3 sig figs) so the magnitude of the average combined non-conservative force against the skier during the given interval is 409 N

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Well I’ve lost my homework sheet for science, I’m just gonna use my random sheet from science to get away with it, gotta give it in tomorrow

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Trump lawyers file paperwork just because he say so they don"t do their homework before filing this is why they can"t WIN

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Armed with vast knowledge in all academic disciplines, our writers can do homework on any subject or topic in a way that is guaranteed to earn you high scores.

Years of experience in helping students like you have got us prepared to sort out any issue you might be dealing with, so you never have to worry about a thing.